Question

141

What's the most straightforward way to copy an ArrayBuffer object?

rated 0 times [ 147] [ 6] / answers: 1 / hits: 49728 / 12 Years ago, wed, april 11, 2012, 12:00:00

I'm working with ArrayBuffer objects, and I would like to duplicate them. While this is rather easy with actual pointers and memcpy, I couldn't find any straightforward way to do it in Javascript.

Right now, this is how I copy my ArrayBuffers:

function copy(buffer)

{

    var bytes = new Uint8Array(buffer);

    var output = new ArrayBuffer(buffer.byteLength);

    var outputBytes = new Uint8Array(output);

    for (var i = 0; i < bytes.length; i++)

        outputBytes[i] = bytes[i];

    return output;

}

Is there a prettier way?

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margaritakristinak

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answered 12 Years ago shianncaylinc · Accepted Answer

ArrayBuffer is supposed to support slice (http://www.khronos.org/registry/typedarray/specs/latest/) so you can try,

buffer.slice(0);

which works in Chrome 18 but not Firefox 10 or 11. As for Firefox, you need to copy it manually. You can monkey patch the slice() in Firefox because the Chrome slice() will outperform a manual copy. This would look something like,

if (!ArrayBuffer.prototype.slice)

    ArrayBuffer.prototype.slice = function (start, end) {

        var that = new Uint8Array(this);

        if (end == undefined) end = that.length;

        var result = new ArrayBuffer(end - start);

        var resultArray = new Uint8Array(result);

        for (var i = 0; i < resultArray.length; i++)

           resultArray[i] = that[i + start];

        return result;

    }

Then you can call,

buffer.slice(0);

to copy the array in both Chrome and Firefox.