55
rated 0 times
[
60]
[
5]
/ answers: 1 / hits: 15347
/ 13 Years ago, thu, september 8, 2011, 12:00:00
I have the folowing selector
var likeComperssionOption = $('select[id*=ComparisionType]').eq(0)
.find(option:contains('LIKE'));
this checks for an option which contains the word 'like' right?
How do i find an option which is exactly with the word 'like'?
Somthing like this:
var likeComperssionOption = $('select[id*=ComparisionType]').eq(0)
.find(option:equals('LIKE'));
More From » jquery