Question

100

Regex matching curly bracket

rated 0 times [ 105] [ 5] / answers: 1 / hits: 37090 / 13 Years ago, fri, march 25, 2011, 12:00:00

Looking for help in matching the curly brackets in a regular expression pattern.
I've tried different combinations of escapes, and symbol matching with little luck. Perhaps because it's Friday afternoon and I'm overlooking something; but your ideas would be greatly appreciated. The code below:

function stringFormat(str, arr) {

   for (var i = 0; i < arr.length; i++) {

        var regExp = new RegExp('^{' + i + '}$', 'g');

        str = str.replace(regExp, arr[i]);   

    }

    return str;  

}



var str = '<p>The quick {0}, brown {1}</p>';



$('#test').html(stringFormat(str, ['brown', 'fox']));

I've also started a fiddle on this, http://jsfiddle.net/rgy3y/1/

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grayson

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answered 13 Years ago mckinley · Accepted Answer

Instead of trying to match a bunch of different numbers, why not just do it all in one fell swoop:

function stringFormat(str, arr) {

  return str.replace(

      /{([0-9]+)}/g,

      function (_, index) { return arr[index]; });

}

On your example,

var str = '<p>The quick {0}, brown {1}</p>';



// Alerts <p>The quick brown, brown fox</p>

alert(stringFormat(str, ['brown', 'fox']));

This has the benefit that nothing weird will happen if arr contains a string like '{1}'. E.g.

stringFormat('{0}', ['{1}', 'foo']) === '{1}' consistently instead of 'foo' as with the fixed version of the original, but inconsistently with stringFormat('{1}', ['foo', '{0}']) === '{0}'