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72

REGEX: Capture Filename from URL without file extension

rated 0 times [ 78] [ 6] / answers: 1 / hits: 26933 / 14 Years ago, wed, september 8, 2010, 12:00:00

I am trying to create a Javascript Regex that captures the filename without the file extension. I have read the other posts here and 'goto this page: http://gunblad3.blogspot.com/2008/05/uri-url-parsing.html' seems to be the default answer. This doesn't seem to do the job for me. So here is how I'm trying to get the regex to work:

Find the last forward slash '/' in the subject string.

Capture everything between that slash and the next period.

The closest I could get was : /([^/]).w$ Which on the string 'http://example.com/index.htm' exec() would capture /index.htm and index.

I need this to only capture index.

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keric

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answered 14 Years ago bradenc · Accepted Answer

var url = http://example.com/index.htm;

var filename = url.match(/([^/]+)(?=.w+$)/)[0];

Let's go through the regular expression:

[^/]+    # one or more character that isn't a slash

(?=       # open a positive lookahead assertion

  .      # a literal dot character

  w+     # one or more word characters

  $       # end of string boundary

)         # end of the lookahead

This expression will collect all characters that aren't a slash that are immediately followed (thanks to the lookahead) by an extension and the end of the string -- or, in other words, everything after the last slash and until the extension.

Alternately, you can do this without regular expressions altogether, by finding the position of the last / and the last . using lastIndexOf and getting a substring between those points:

var url = http://example.com/index.htm;

var filename = url.substring(url.lastIndexOf(/) + 1, url.lastIndexOf(.));