Is there a way in jQuery to get all CSS from an existing element and apply it to another without listing them all?
I know it would work if they were a style attribute with attr(), but all of my styles are in an external style sheet.
A couple years late, but here is a solution that retrieves both inline styling and external styling:
function css(a) {
var sheets = document.styleSheets, o = {};
for (var i in sheets) {
var rules = sheets[i].rules || sheets[i].cssRules;
for (var r in rules) {
if (a.is(rules[r].selectorText)) {
o = $.extend(o, css2json(rules[r].style), css2json(a.attr('style')));
}
}
}
return o;
}
function css2json(css) {
var s = {};
if (!css) return s;
if (css instanceof CSSStyleDeclaration) {
for (var i in css) {
if ((css[i]).toLowerCase) {
s[(css[i]).toLowerCase()] = (css[css[i]]);
}
}
} else if (typeof css == string) {
css = css.split(; );
for (var i in css) {
var l = css[i].split(: );
s[l[0].toLowerCase()] = (l[1]);
}
}
return s;
}
Pass a jQuery object into css() and it will return an object, which you can then plug back into jQuery's $().css(), ex:
var style = css($(#elementToGetAllCSS));
$(#elementToPutStyleInto).css(style);
:)
